Crane for cargo duty
at maximum radius
| Q = 220 kN | lmax = 23 m |
| A = 75 kN | amax = 11 m |
| O = 450 kN | o = 0.75 m |
| G = 900 kN | g = 3 m |
| W = 27 kN | r = 6.5 m |
1) Maximum operating load including wind
Fa = Q + A + O + G
Fa = 220 + 75 + 450 + 900
Fa = 1,645 kN
Mk = Q · lmax + A · amax + W · r - O · o - G · g
Mk = 220 · 23 + 75 · 11 + 27 · 6.5 - 450 · 0.75 - 900 · 3
Mk = 3,023.0 kNm
2) Load case incl. 25% test load without wind
Fa = Q · 1.25 + A + O + G
Fa = 275 + 75 + 450 + 900
Fa = 1,700 kN
Mk = Q · 1.25 · l max + A · amax - O · o - G · g
Mk = 275 · 23 + 75 · 11 - 450 · 0.75 - 900 · 3
Mk = 4,112.5 kNm
3) Maximum operating load without wind
Fa = 1,645 kN
Mk = Q · lmax + A · amax - O · o - G · g
Mk = 220 · 23 + 75 · 11 - 450 · 0.75 - 900 · 3
Mk = 2,847.5 kNm
When selecting the bearing, load case 2) should be used for static evaluation, and load case 3) for service life.
The static load capacity of the bearing, taking into account load factor fstat = 1.25 is checked against the "static limiting load curve", reference load:
Load case 2)
Fa' = 1,700 kN · 1.25 = 2,125 kN
Mk' = 4,112.5 kNm · 1.25 = 5,140.6 kNm
A load factor of fL = 1.15 is used for a service life of 45,000 revolutions under full load, reference load:
Load case 3)
Fa' = 1,645 kN · 1.15 = 1,891.7 kN
Mk' = 2,847.5 kNm · 1.15 = 3,274.6 kNm
The number of bolts and strength class will be determined for the max. load without a factor:
Load case 2)
Fa = 1,700 kN
Mk = 4,112.5 kNm

